Instructor: Matthew Bruce / mbruce@uw.edu
University of Washington
Assumptions in the following derivation:
The physics of sound waves involves 3 phenomenon:
Equation of the motion produced by an imbalanced pressure gradient:
Small excursion in density leads to small excursion in pressure:
\[ \small{1. \: P = P_o+P_e \quad \rho = \rho_o + \rho_e \\ 2. \: P_o+P_e = f(\rho_o + \rho_e ) = f(\rho_o) + \rho_e f^{\prime} (\rho) |_{\rho=\rho_o}\\ 3. \: P_e =\rho_e f^{\prime} (\rho) |_{\rho=\rho_o} \\ 4. \: P_e =\kappa \rho_e \quad \textrm{where} \; \kappa = f^{\prime} (\rho) |_{\rho=\rho_o} = \frac{\partial P(\rho)}{\partial \rho}|_{\rho=\rho_o} } \]Differential displacements in space lead to perturbations in density:
We can sub 2 into 3, \( \rho_o \frac{\partial^{2} \chi (x,t))}{\partial t^2} = \kappa \frac{\partial \rho_e}{\partial x} \).
We can sub 1 into this to remove \( \rho_e \), \( \frac{\partial^{2} \chi (x,t))}{\partial t^2} = \kappa \frac{\partial^2 \chi}{\partial x^2} \) where \( \: c_s = \sqrt{ \kappa} = (\frac{dP}{d \rho})^{1/2}= (\frac{K}{\rho})^{1/2}\).
Solutions to the wave equation have the following form \( \chi(x,t) = f(x-vt) \) or \( f(x+vt) \).
Lets see if our equation support these solutions:
\[ \scriptsize {1. \frac{\partial^2 \chi(x,t)}{\partial x^2} = f^{\prime \prime} (x-vt) \\ 2. \frac{\partial^2 \chi(x,t)}{\partial t^2} = v^2 f^{\prime \prime} (x-vt) \\ } \]\( y(x_1,t) = sin(k(x_1-ct)) \) where $k=\frac{2 \pi}{\lambda}$
For a fixed point in space, the sinusoidal wave will oscillate with a period T:
\[ \scriptsize {1.\; kcT = 2 \pi \\ 2. \; \textrm{So, the frequency: } \\ \quad f = \frac{1}{T} = \frac{kc}{2 \pi} = \frac{c}{\lambda} \\ 3. \; \lambda = \frac{c}{f}, \; \textrm{source determines} \; f} \]Newton assumed isothermal changes in pressure/density and got pretty close to the true speed of sound in air.
But over the long wave lengths/time scales air behaves more adiabatically as the rarefaction/compressions pass.
\[ \scriptsize { PV^\gamma = constant \text{, which with density} P = const \: \rho^\gamma \\ \frac{dP}{d \rho} = \frac{\gamma P}{\rho} \mbox{ which gives for the speed of sound:}\\ \mbox{ Using the ideal gas law, } c_s = \frac{\gamma P}{\rho} = \frac{\gamma k T}{m} = \frac{\gamma R T}{\mu} = (\frac{\gamma}{3})^{1/2} v_{avg} } \]Newton assumed isothermal changes in pressure/density and got pretty close to the true speed of sound in air.
But over the long wave lengths/time scales air behaves more adiabatically as the rarefaction/compressions pass.
\[ \scriptsize { PV^\gamma = constant \text{, which with density} P = const \: \rho^\gamma \\ \frac{dP}{d \rho} = \frac{\gamma P}{\rho} \mbox{ which gives for the speed of sound:}\\ c_s = \frac{\gamma P}{\rho} = \frac{\gamma k T}{m} = \frac{\gamma R T}{\mu} = (\frac{\gamma}{3})^{1.2} v_{av} \mbox{ using the ideal gas law.} } \]Newton assumed isothermal changes in pressure/density and got pretty close to the true speed of sound in air.
But over the long wave lengths/time scales air behaves more adiabatically as the rarefaction/compressions pass.
\[ \scriptsize { PV^\gamma = constant \text{, which with density} P = const \: \rho^\gamma \\ \frac{dP}{d \rho} = \frac{\gamma P}{\rho} \mbox{ which gives for the speed of sound:}\\ c_s = \frac{\gamma P}{\rho} = \frac{\gamma k T}{m} = \frac{\gamma R T}{\mu} = (\frac{\gamma}{3})^{1.2} v_{av} \mbox{ using the ideal gas law.} } \]For more detail see Feynman's Physics Lectures vol 1 chapter 47
More on the speed of sound for different materials and mediums.
No satisfactory equation of state exists for fluids like we used for air. Measured values of fluid properties are used instead.
Note: Compressibility and Bulk modulus are inversely related.
\( \small{\mbox{Adiabatic Compressibility } \kappa = \frac{1}{V}\frac{\partial V}{\partial p} = \frac{1}{\rho_0}\frac{\partial \rho}{\partial p}} \)Medium | Speed of sound | Wavelength (1 MHz) |
---|---|---|
Air | 300 m/s | 0.3x10^6 |
Water | 1480 m/s | 1.48x10^6 |
Tissue | 1540 m/s | 1.54x10^6 |
Bone | 4000 m/s | 4.0x10^6 |
Pressure: \( p=\frac{F}{A} \) N/m 2 or Pascals
Atmospheric pressure is 100 kPa, while sound is measured as rms of the deviation from equilibrium:
\[ \scriptsize{ p_{rms} = \sqrt{\frac{1}{t_{avg}} \int_{0}^{t_{avg}} p^2 \,dt } \\ \mbox{for sinusoidal signals of amplitude A, the rms pressure is } A/\sqrt{2} \\ SPL := 20 \log_{10} \left( \frac{p_{rms}}{p_{ref}} \right) } \]Combining the pressure and particle velocity conditions gives:
\( R_p = \frac{Z_2-Z_1}{Z_2+Z_1}, \; \\ T_p = \frac{2Z_2}{Z_2+Z_1}, \; \)Assume an interface with acoustic impedance\( Z_2= 19 Z_1 \)
\( \; R_p = 0.9 \; \; T_p = 1.9 \)Reflection/transmission is at normal incidence (90 deg) but we plot
When the angle of incidence is oblique we have the refraction:
\( \; \theta_r = \theta_t, \; \frac{\sin \theta_t}{c_2} = \frac{\sin \theta_i}{c_1} \)The reflection and transmission coefficients then become:
Ref: Cobbold
3 MHz and 0.5 dB/MHz/cm